v^2-5v-13=0

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Solution for v^2-5v-13=0 equation: 



v^2-5v-13=0

a = 1; b = -5; c = -13;
Δ = b2-4ac
Δ = -52-4·1·(-13)
Δ = 77
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{77}}{2*1}=\frac{5-\sqrt{77}}{2}
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{77}}{2*1}=\frac{5+\sqrt{77}}{2}
$

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